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Escape burn delta-v calculator from a circular orbit

From a circular Earth orbit with a radius of 6,771 km, escaping takes a prograde burn of 3178.094418806551 m/s, not the full escape speed. Enter the central body's μ and the orbital radius to get circular speed, escape speed and the delta-v. Free in your browser.

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If you enter
Mu
398,600,441,800,000
Radius
6,771,000
You get
Mu m3 s2
398,600,441,800,000
Radius m
6,771,000
Circular speed m s
7,672.598648385
Escape speed m s
10,850.6930671916

An escape burn from a circular orbit does not require adding the full local escape speed. The spacecraft already has circular orbital velocity, so the ideal prograde impulse is the difference between escape speed and circular speed at the same radius. This calculator evaluates that difference from the central body's standard gravitational parameter and the orbit's centre-to-spacecraft radius. It reports both component speeds, the required delta-v in metres per second and kilometres per second, and the assumptions behind the result. The calculation is deterministic, uses no network or stored lookup table, and rejects a zero or negative orbital radius rather than returning an undefined physical result.

Why escape-burn delta-v is a difference between two speeds

A spacecraft in a circular orbit is already moving sideways at circular speed, given by the square root of the standard gravitational parameter divided by orbital radius. At that same location, the speed for a parabolic escape trajectory is the square root of twice the gravitational parameter divided by radius. A tangential prograde impulse raises the spacecraft's specific orbital energy from the negative value of the circular orbit to zero, the boundary between a bound ellipse and an unbound hyperbola.

Therefore the ideal escape-burn delta-v is escape speed minus circular speed, not escape speed by itself. Algebraically, this is also circular speed multiplied by the square root of two minus one. The subtraction matters: treating the spacecraft as stationary at its orbital radius would greatly overstate the propulsive requirement and ignore the useful kinetic energy it already possesses.

This capability displays circular speed and escape speed alongside the difference so that students, analysts, and software tests can inspect every important number. The result describes a zero-hyperbolic-excess departure, meaning speed approaches zero infinitely far from the central body in this two-body model. It is the minimum ideal impulsive departure, not a complete mission budget or launch-vehicle performance prediction.

Choose consistent inputs and interpret the response

Provide mu, the central body's standard gravitational parameter, in cubic metres per second squared, and radius, the distance from the body's centre to the spacecraft, in metres. Radius is not altitude above the surface. If a problem gives altitude, add the body's reference radius before using the calculator.

For Earth, a commonly used gravitational parameter is about 3.986004418 times ten to the fourteen cubic metres per second squared. A spacecraft four hundred kilometres above a reference Earth radius of roughly 6,371 kilometres therefore uses an orbital radius near 6,771 kilometres, converted to 6,771,000 metres. All numeric outputs use deterministic twelve-decimal-place rounding, although source data and the ideal model usually justify fewer significant figures.

Missing, nonnumeric, non-finite, or out-of-range inputs are rejected. The gravitational parameter must be positive, and the orbital radius must be strictly greater than zero because division by zero and a negative radial distance have no meaning in this calculation.

Understand the idealisations before using the number

The calculation assumes an instantaneous prograde burn from a perfectly circular orbit in a Newtonian two-body system. Real engines apply thrust over time, so a long burn changes position and direction while propellant is being expended and can introduce gravity losses. The result also ignores atmosphere, oblateness, rotation of the central body, perturbations from other bodies, navigation margins, steering losses, residuals, and the propellant needed for attitude control or trajectory correction.

It targets a parabolic escape with zero speed at infinity. Interplanetary missions usually require a specified positive hyperbolic excess speed, often written v-infinity, to enter a transfer trajectory after leaving the planet's sphere of influence; that departure burn is larger and needs a different equation. Likewise, this value is not the delta-v from a planetary surface, because a surface vehicle is not initially in a circular orbit and must pay ascent and loss terms.

Use this calculator for quick feasibility estimates, classroom mechanics, independent checks of orbital software, and the escape line in a preliminary delta-v budget. Then apply appropriate mission-specific modelling and margins before making engineering decisions. The browser calculation uses the same pure solver, helping repeated checks remain consistent across environments.

Check an orbital-mechanics exercise

Compare a hand calculation of circular speed, local escape speed, and their difference with a deterministic result.

Draft a preliminary mission budget

Estimate the ideal zero-v-infinity departure burn from a known circular parking orbit before adding losses and margins.

Test astrodynamics software

Create reproducible reference outputs and confirm that invalid radii are rejected instead of producing NaN or Infinity.

What formula does the calculator use?

It uses Δv = √(2μ/r) − √(μ/r), the local escape speed minus the current circular speed at the same orbital radius.

Is radius altitude above the surface?

No. Radius is measured from the central body's centre. Add the body's reference radius to altitude before calculating.

Does this calculate an interplanetary departure burn?

Only the minimum escape burn with zero hyperbolic excess speed. A transfer requiring positive v-infinity needs additional departure speed.

How much delta-v does it take to escape from a 6,771 km Earth orbit?

3178.094418806551 m/s, or 3.178094418807 km/s. At that radius circular speed is 7672.598648385013 m/s and escape speed is 10850.693067191563 m/s; the burn only has to make up the difference.

Why is the burn smaller than the escape speed?

Because the spacecraft is already moving at circular speed. A prograde burn only has to add the difference between escape and circular speed, which equals circular speed times the square root of two minus one.

Everything on this page is available programmatically. This section is for teams who want to wire it into their own systems; everyone else can just use the tool above.

POSThttps://api.kit.forhosting.com/astro/escape-burn-deltav

Prefer to automate it? One authenticated POST creates the task; the result comes back by webhook or a signed link. The same capability also runs here on the web, by email and from Telegram — and soon from our app too.

curl -X POST https://api.kit.forhosting.com/astro/escape-burn-deltav \
  -H "Authorization: Bearer $KIT_KEY" \
  -H "Content-Type: application/json" \
  -d '{"mu":398600441800000,"radius":6771000}'
{
  "mu": 398600441800000,
  "radius": 6771000
}
{
  "task_id": "tsk_a1b2c3d4e5f6a1b2c3d4e5f6",
  "type": "astro.escape_burn_deltav",
  "status": "queued",
  "_links": {
    "result": "/tasks/tsk_…/result"
  }
}

The API is asynchronous: the call returns a task_id immediately and the result arrives by webhook. Polling is capped at 1 req/s per task.

Per request$0.002

Published price — no tokens, no invented credits. A failed task is never charged.

HTTPCodeMeaning
401unauthorizedMissing or invalid API key.
402insufficient_balanceYour balance doesn't cover the task price.
404unknown_typeThat task type doesn't exist.
429rate_limitedToo many requests. Use the webhook instead of polling.

Choose consistent inputs and interpret the response

The response returns the normalized inputs, circular_speed_m_s, escape_speed_m_s, delta_v_m_s, and delta_v_km_s. It also includes the formula and an assumptions list. The solver accepts explicit aliases gravitational_parameter, orbital_radius, and r, but canonical field names are clearest for generated SDKs and web forms.

Understand the idealisations before using the number

API pricing is $0.002 per successful request, while invalid input is reported as invalid_input.

What happens when orbital radius is zero or negative?

The request fails with invalid_input because the formula requires a strictly positive centre-to-spacecraft distance.

How much does an API calculation cost?

Each successful API request costs $0.002. The same deterministic calculation is available free in the browser.

Read the full KIT documentation →