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Double Integral Midpoint Rule Calculator

Approximate a double integral over a rectangle by sampling the center of every grid cell: x^2 + y^2 for x from 0 to 2 and y from 0 to 1, on a 2 by 2 grid, gives 3.125. Every cell is listed. Free in your browser.

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If you enter
Integrand
x^2 + y^2
X min
0
X max
2
Y min
0
Y max
1
X subintervals
2
You get
Value sum
6.25
Approximation
3.125

This double integral midpoint rule calculator approximates the integral of f(x,y) over a rectangular region by dividing both coordinate directions into equal subintervals. It evaluates the function at the center of every resulting cell, multiplies the sum of those values by the area of one cell, and returns the complete calculation. Enter an expression, four bounds, and the grid dimensions to obtain the approximation together with the spacing, sample count, midpoint coordinates, function values, and contribution from each subrectangle.

Set up the rectangle and midpoint grid

A composite midpoint approximation begins with a rectangle [a,b] by [c,d]. The calculator computes the widths dx=(b-a)/m and dy=(d-c)/n. Their product is the area of every subrectangle.

Within column i and row j, the sample coordinate is halfway between the corresponding edges, so no corner or boundary value is used. The integrand can contain x, y, ordinary arithmetic, powers, the constants pi and e, and supported functions such as sin, cos, exp, log, sqrt, abs, min, and max. Multiplication must be explicit: write 2*x rather than 2x.

Bounds must increase from minimum to maximum, and each subdivision count must be a positive integer. These requirements make the region, grid, and orientation unambiguous before any numerical work begins. The reported sample list uses one-based column and row indices, making each value easy to match to a hand-drawn grid or classroom table.

Understand how the approximation is formed

For every grid cell, the calculator evaluates f at that cell's center. It adds all midpoint values and multiplies their sum by dx times dy. Equivalently, each row in the returned sample list includes a contribution equal to the function value multiplied by the common cell area, and adding those contributions produces the displayed approximation.

Midpoint sampling often performs better than choosing a corner because the center balances variation across a small cell, but the result is still a numerical approximation. Accuracy depends on the shape of the function and the grid resolution. Smooth functions generally improve as the subdivisions become finer, while steep gradients, oscillation, singular behavior, or discontinuities may require much more care.

The calculator rejects any midpoint where the expression is undefined or produces an infinite value. It does not claim an error bound or compare against an exact antiderivative. To assess convergence, run the same rectangle with progressively finer grids and compare the approximations.

Agreement across refinements is useful evidence, although it is not by itself a formal proof of accuracy.

Read, verify, and reuse the result

The result separates the inputs, grid geometry, accumulated value sum, final approximation, and individual samples. Start by checking that the returned rectangle and subdivision counts match the intended problem. Next verify dx, dy, and cell area; a mistaken bound or swapped count becomes apparent there.

The sample count must equal the product of the two subdivision counts. Each sample reports its midpoint coordinates, evaluated function value, and weighted contribution, which provides an audit trail for homework, worksheets, numerical-method demonstrations, and software tests. The precision option changes only how returned decimals are presented; evaluations and accumulation retain the available floating-point precision internally.

A coarse grid is valuable for checking a hand calculation because every term remains visible. A finer grid is better for studying convergence, but it also creates a longer sample list and more computation. No network service, random source, stored state, or clock participates in the calculation, so results are reproducible within standard JavaScript floating-point arithmetic.

Check a multivariable calculus exercise

Compare a hand-built midpoint table with the returned centers, values, contributions, and total.

Explore grid refinement

Repeat one rectangular integral with increasing subdivision counts to observe how its numerical approximation changes.

What does the calculator compute?

It applies the composite midpoint rule on a rectangular m-by-n grid and returns the weighted sum of all center evaluations.

Which expressions are supported?

Use x, y, numeric constants, explicit arithmetic, powers, pi, e, and supported named functions including trigonometric, exponential, logarithmic, square-root, absolute-value, minimum, and maximum functions.

Does a finer grid guarantee the exact integral?

No. Refinement often improves a smooth-function approximation, but this calculator neither proves convergence nor supplies a formal error bound.

Why was my expression rejected at a midpoint?

The expression produced a non-finite value there, as can happen with division by zero, an invalid logarithm, or a square root outside its real domain.

How is the midpoint estimate of 3.125 for x^2 + y^2 worked out?

For x from 0 to 2 and y from 0 to 1 on a 2 by 2 grid, each cell measures 1 by 0.5, so its area is 0.5. The four center values add up to 6.25, and 6.25 times 0.5 gives 3.125.

Everything on this page is available programmatically. This section is for teams who want to wire it into their own systems; everyone else can just use the tool above.

POSThttps://api.kit.forhosting.com/calculus/double-integral-midpoint

Prefer to automate it? One authenticated POST creates the task; the result comes back by webhook or a signed link. The same capability also runs here on the web, by email and from Telegram — and soon from our app too.

curl -X POST https://api.kit.forhosting.com/calculus/double-integral-midpoint \
  -H "Authorization: Bearer $KIT_KEY" \
  -H "Content-Type: application/json" \
  -d '{"integrand":"x^2 + y^2","x_min":0,"x_max":2,"y_min":0,"y_max":1,"x_subintervals":2,"y_subintervals":2}'
{
  "integrand": "x^2 + y^2",
  "x_min": 0,
  "x_max": 2,
  "y_min": 0,
  "y_max": 1,
  "x_subintervals": 2,
  "y_subintervals": 2
}
{
  "task_id": "tsk_a1b2c3d4e5f6a1b2c3d4e5f6",
  "type": "calculus.double_integral_midpoint",
  "status": "queued",
  "_links": {
    "result": "/tasks/tsk_…/result"
  }
}

The API is asynchronous: the call returns a task_id immediately and the result arrives by webhook. Polling is capped at 1 req/s per task.

Per request$0.002

Published price — no tokens, no invented credits. A failed task is never charged.

max_points10000
max_expression_chars500
HTTPCodeMeaning
401unauthorizedMissing or invalid API key.
402insufficient_balanceYour balance doesn't cover the task price.
404unknown_typeThat task type doesn't exist.
429rate_limitedToo many requests. Use the webhook instead of polling.

Set up the rectangle and midpoint grid

Enter those endpoints as the lower and upper bounds for x and y, then choose how many equal subintervals to use on each axis.

Read, verify, and reuse the result

Automated callers pay $0.002 per request and receive the same deterministic structure for identical inputs.

Create deterministic test fixtures

Generate an auditable midpoint sum for educational software, worksheets, or numerical-method regression tests.

What does it cost to automate?

Each API request costs $0.002. The browser version can run the same deterministic calculation without an API call.

Read the full KIT documentation →