ForHosting KIT · Engineering & construction

Cylindrical pipe conduction calculator

A 10 m pipe with conductivity 45 W/m·K, radii of 0.05 and 0.06 m and an 80 °C drop across the wall passes over a million watts. You also see the thermal resistance and both surface fluxes. Free in your browser.

  • Free
  • Runs in your browser
  • No sign-up
  • Your data stays on your device
Use it from WebAPIEmailTelegramApp soon
If you enter
K
45
Length
10
Inner radius
0.05
Outer radius
0.06
Dt
80
You get
Thermal conductivity
45
Temperature difference
80
Radius ratio
1.2
Ln radius ratio
0.1823215568

A cylindrical pipe conduction calculator turns thermal conductivity, axial length, inner and outer radii, and the temperature drop across the wall into the steady radial heat transfer rate predicted by Fourier’s law in cylindrical coordinates. Enter k for the pipe material, L for the length of the pipe section, ri and ro for the inner and outer radii of the wall, and ΔT for the temperature difference between the inner and outer surfaces. The tool returns Q equals two pi k L ΔT over the natural log of ro over ri, the cylindrical thermal resistance, the heat fluxes at both surfaces, a readable equation string, and substitution steps you can copy into a notebook. Homework checks, insulated-pipe estimates, steam-line heat-loss sketches, and coding-kata expected values all need that logarithmic radial model instead of the plane-wall quotient Q equals k A ΔT over L.

What radial Fourier conduction says about a pipe wall

Fourier’s law in cylindrical coordinates says that the radial heat flux is minus k times dT/dr. For steady conduction through a long hollow cylinder with constant conductivity and no generation, energy conservation forces the heat transfer rate Q to be the same at every radius, so the temperature field must vary as the logarithm of r rather than as a straight line in r.

Integrating from the inner surface at ri and Ti to the outer surface at ro and To produces the classic pipe-wall formula Q equals two pi k L times (Ti minus To) divided by the natural logarithm of ro over ri. The same result is often written with a conduction resistance R_cyl equal to ln(ro/ri) over two pi k L, so Q equals ΔT over R_cyl, which makes it easy to place the metal wall in series with inner and outer convection films in a later resistance network.

Thermal conductivity k is a material property: tens of watts per metre-kelvin for many steels, a few hundred for copper, and a fraction of one for common plastics. Length L is the axial length of the pipe section you are analysing, not the wall thickness; the thickness enters only through the two radii. Temperature difference ΔT is the inner-surface temperature minus the outer-surface temperature; a positive ΔT with positive k and L yields heat flowing radially outward.

The logarithm is defined only when both radii are positive and ro is strictly larger than ri. If the radii are equal there is no wall and the formula would divide by zero; if they are inverted the argument of the log is less than one and the sign of Q would flip for the wrong geometric reason.

Practical tips, limits, and related searches

Keep k, L, ri, ro, and ΔT inside the published absolute range so the product two pi k L ΔT and the logarithm cannot overflow into a non-finite heat rate the solver must reject. Use a coherent unit set: watts per metre-kelvin, metres, and kelvin (or Celsius difference) yield watts for Q, kelvin per watt for thermal resistance, and watts per square metre for the surface fluxes. Imperial inputs need the same coherence if you want BTU per hour.

This tool does not convert units, look up material properties from a metal name, add convection or radiation films, treat multi-layer insulation, or solve the transient radial equation. When the wall is thin relative to the radius, ln(ro/ri) is approximately (ro minus ri) over ri and the cylindrical result approaches the plane-wall formula with area equal to two pi ri L and thickness equal to ro minus ri; use that check as a sanity test, not as a substitute for the log form on thick tubes.

Prefer this capability when you already have k, L, ri, ro, and ΔT and only need Q; the sibling plane-wall conduction tool is the right page when the geometry is a flat slab.

Steam and hot-water pipe heat-loss sketches

Estimate the radial conduction through a known metal wall before adding insulation layers or comparing the leak against boiler capacity.

Homework checks for cylindrical conduction

Students enter textbook k, L, ri, ro, and ΔT, then compare hand-written Q, R_cyl, and substitution steps against a deterministic result.

Why is there a logarithm of the radius ratio?

In radial coordinates the heat-transfer area grows with r, so temperature cannot be linear in r. Integrating Fourier’s law from ri to ro produces ln(ro/ri) in the denominator.

How is this different from plane-wall conduction Q = k A ΔT / L?

A flat slab has constant area. A pipe wall has area 2πrL that changes with radius, so the correct closed form is the logarithmic cylindrical formula, not the plane-wall quotient.

Is the cylindrical pipe conduction calculator free?

The browser tool is free and runs locally.

Why must the outer radius be larger than the inner radius?

Because the wall thickness is the gap between them. Equal radii mean there is no wall and the formula would divide by zero; inverted radii would make the logarithm negative, so both cases are rejected instead of shown as a heat rate.

Is the pipe length the same as the wall thickness?

No. Length is the axial length of the pipe section you are analysing. The wall thickness enters only through the two radii, so a thicker wall shows up as a larger outer radius.

Everything on this page is available programmatically. This section is for teams who want to wire it into their own systems; everyone else can just use the tool above.

POSThttps://api.kit.forhosting.com/eng/cylinder-conduction

Prefer to automate it? One authenticated POST creates the task; the result comes back by webhook or a signed link. The same capability also runs here on the web, by email and from Telegram — and soon from our app too.

curl -X POST https://api.kit.forhosting.com/eng/cylinder-conduction \
  -H "Authorization: Bearer $KIT_KEY" \
  -H "Content-Type: application/json" \
  -d '{"k":45,"length":10,"inner_radius":0.05,"outer_radius":0.06,"dt":80}'
{
  "k": 45,
  "length": 10,
  "inner_radius": 0.05,
  "outer_radius": 0.06,
  "dt": 80
}
{
  "task_id": "tsk_a1b2c3d4e5f6a1b2c3d4e5f6",
  "type": "eng.cylinder_conduction",
  "status": "queued",
  "_links": {
    "result": "/tasks/tsk_…/result"
  }
}

The API is asynchronous: the call returns a task_id immediately and the result arrives by webhook. Polling is capped at 1 req/s per task.

Per request$0.002

Published price — no tokens, no invented credits. A failed task is never charged.

max_abs1000000000000
HTTPCodeMeaning
401unauthorizedMissing or invalid API key.
402insufficient_balanceYour balance doesn't cover the task price.
404unknown_typeThat task type doesn't exist.
429rate_limitedToo many requests. Use the webhook instead of polling.

Equal or inverted radii are rejected with a clear invalid_input error so a missing wall thickness never becomes a divide-by-zero or a negative logarithm.

What radial Fourier conduction says about a pipe wall

This calculator encodes those domain rules as invalid_input instead of returning infinity, NaN, or a silently signed logarithm that would look like a valid heat rate.

How to call the API and what comes back

Thermal conductivity, length, and inner radius must be strictly positive. The outer radius must be strictly greater than the inner radius so ln(ro/ri) is defined and positive. The body also includes formula, a substituted equation string, law set to Fourier cylindrical, a short English message, and an ordered steps array you can assert in tests or lab notebooks. Send a JSON body with five required finite numbers: k (aliases thermal_conductivity, conductivity, lambda), length (aliases L, pipe_length, axial_length), inner_radius (aliases ri, r_inner, r_i, inner), outer_radius (aliases ro, r_outer, r_o, outer), and dt (aliases delta_t, dT, temperature_difference, deltaT, temp_diff). Absolute values must stay within the published limit of one trillion so intermediate products, the logarithm, and the quotient remain finite in IEEE double precision on the Worker and in the browser. On success the response echoes the rounded inputs, reports radius_ratio and ln_radius_ratio, sets q and heat_transfer_rate to the same rounded heat rate in watts when SI units are used, reports thermal_resistance as ln(ro/ri) over two pi k L, and reports inner_heat_flux and outer_heat_flux as Q divided by the corresponding cylindrical surface area two pi r L. Failed validation — missing fields, non-finite numbers, values outside absolute limits, non-positive k, length or inner radius, outer radius not greater than inner radius, or a non-finite heat rate — returns invalid_input and is never charged. Pricing is a flat $0.002 per successful request with unit item.

Practical tips, limits, and related searches

Prefer sending JSON numbers rather than pre-formatted strings when you control the client; string numbers are accepted only when they match a strict finite numeric pattern. When teaching, pair examples: k equals forty-five, L equals ten metres, ri equals zero point zero five metres, ro equals zero point zero six metres, and ΔT equals eighty kelvin is the published sample; a deliberate ro equal to ri demonstrates the hard invalid_input path. This landing targets people searching for a cylindrical pipe conduction calculator, radial heat flow through a pipe wall, or the formula Q equals two pi k L ΔT over ln(ro/ri). Failed tasks that return invalid_input do not consume prepaid balance. Round-trip checks are easy: recompute two pi k L ΔT divided by ln(ro/ri) by hand and confirm it equals the published heat_transfer_rate within the same twelve-decimal rounding.

Unit tests for student thermal solvers

Generate known-good Q = 2πkLΔT / ln(ro/ri) cases plus deliberate equal-radius rejections for coding kata fixtures and continuous-integration oracles.

What formula does this cylindrical pipe conduction calculator use?

Steady one-dimensional Fourier conduction through a hollow cylinder: Q = 2 π k L ΔT / ln(ro / ri), with cylindrical resistance R = ln(ro/ri) / (2 π k L).

What happens if the outer radius is not larger than the inner radius?

The logarithm would be zero or negative. This tool returns invalid_input instead of infinity or a silently signed heat rate.

Read the full KIT documentation →