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Telescoping series sum

The first 10 terms of 1/(k(k+1)) add up to exactly 10/11. Enter how many terms you want and get the partial sum as a reduced fraction and a decimal, worked out with exact whole-number arithmetic, never by adding rounded terms. Free in your browser.

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If you enter
N
10
You get
Sum
0.9090909091
Fraction
10/11
Numerator
10
Denominator
11

The telescoping series sum calculator evaluates the partial sum of one over k times k plus one from k equals one through n, and returns the exact closed form n over n plus one as both a reduced fraction and a decimal. Because each term factors as a difference of unit fractions, one over k minus one over k plus one, the intermediate terms cancel and the entire sum collapses to one minus one over n plus one. Classic checks include one half for n equals one, two thirds for n equals two, three quarters for n equals three, and nine tenths for n equals nine. This capability is a pure parse engine: it uses deterministic integer arithmetic, never samples randomness, never reads the clock, and never calls the network.

What the telescoping sum is and why it equals n/(n+1)

A telescoping series is a sum in which consecutive terms cancel after partial-fraction decomposition, leaving only the first positive pieces and the last negative piece.

The series of terms one over k times k plus one is the textbook example: each summand decomposes as one over k minus one over k plus one, so writing out the partial sum from k equals one to n produces one minus one half, plus one half minus one third, plus one third minus one fourth, and so on through one over n minus one over n plus one. Every intermediate fraction appears once with a plus sign and once with a minus sign, so they cancel in pairs.

What remains is simply one minus one over n plus one, which rewrites as the single fraction n over n plus one. For n equals one the sum is one half; for two it is two thirds; for five it is five sixths; for ten it is ten elevenths. The infinite series therefore converges to one as n grows without bound, and the partial sum is the exact rational n over n plus one for every positive integer n.

You receive the index n, the floating-point sum, the reduced fraction string, the numerator and denominator, the closed-form formula, the original series pattern, the partial-fraction identity, and the supported maximum index. Valid positive indices always succeed with a deterministic result; there is no probabilistic path and no floating-point accumulation that could drift from the textbook identity.

Where telescoping sums fit in study, contests, and automation

Students meet telescoping series early in calculus when they learn partial fractions and the definition of series convergence. Teachers can generate answer keys for worksheets without trusting opaque calculator apps that accumulate floating-point terms or that silently convert large rationals to scientific notation. Contest practice often needs a fast offline source of partial sums of one over k times k plus one so solutions can be checked without writing a loop or looking up OEIS sequences.

Puzzle and game designers use telescoping growth curves for resource costs that approach a horizontal asymptote of one. Developers use the same contract to validate sample data for symbolic algebra libraries, to seed property tests that need known rational partial sums, or to pre-check that a harmonic-style cancellation matches a closed form before a simulation step. Data pipelines that model successive cancellation of overlapping intervals sometimes need a closed-form residual from a depth parameter that maps to consecutive unit-fraction differences.

Pair it with geometric-sequence tools when you need other classical closed forms, and with sum-of-cubes or tetrahedral helpers when you need related integer series identities.

Homework and partial-fraction checks

Compute Σ 1/(k(k+1)) for worksheets and contest checks without hand-cancelling terms or trusting floating-point loops.

Teaching telescoping cancellation

Show students how n maps to n/(n+1) while they change inputs live in the browser at no cost.

What does the telescoping series sum calculator cost?

It is free in your browser on this page.

How is the sum computed?

The engine evaluates the closed form n/(n+1) with exact integer arithmetic. No floating-point loop over reciprocals is used, so the fraction is always exact for integer n.

Is the algorithm randomized?

No. It uses deterministic integer arithmetic. The same n always yields the same fraction and the same decimal value.

What is the sum of the first 10 terms of 1/(k(k+1))?

Exactly 10/11. The ten terms collapse to 1 − 1/11, which the calculator shows as the reduced fraction 10/11 together with its decimal value, so a worksheet answer can be checked at a glance.

What does the infinite telescoping series converge to?

It converges to 1. The partial sum n/(n+1) creeps closer to 1 as you add terms, but every finite sum stays just below it, as with 9/10 after nine terms or 10/11 after ten.

Everything on this page is available programmatically. This section is for teams who want to wire it into their own systems; everyone else can just use the tool above.

POSThttps://api.kit.forhosting.com/math/telescoping-sum

Prefer to automate it? One authenticated POST creates the task; the result comes back by webhook or a signed link. The same capability also runs here on the web, by email and from Telegram — and soon from our app too.

curl -X POST https://api.kit.forhosting.com/math/telescoping-sum \
  -H "Authorization: Bearer $KIT_KEY" \
  -H "Content-Type: application/json" \
  -d '{"n":10}'
{
  "n": 10
}
{
  "task_id": "tsk_a1b2c3d4e5f6a1b2c3d4e5f6",
  "type": "math.telescoping_sum",
  "status": "queued",
  "_links": {
    "result": "/tasks/tsk_…/result"
  }
}

The API is asynchronous: the call returns a task_id immediately and the result arrives by webhook. Polling is capped at 1 req/s per task.

Per request$0.002

Published price — no tokens, no invented credits. A failed task is never charged.

HTTPCodeMeaning
401unauthorizedMissing or invalid API key.
402insufficient_balanceYour balance doesn't cover the task price.
404unknown_typeThat task type doesn't exist.
429rate_limitedToo many requests. Use the webhook instead of polling.

Values of n below one are rejected with invalid_input because the classical partial sum starts at the first positive index. Explore free in the browser for calculus homework, partial-fraction demos, and contest prep, or call the API at $0.002 per successful request when grading scripts and pipelines need reproducible telescoping answers.

What the telescoping sum is and why it equals n/(n+1)

This capability evaluates that closed form with exact integer arithmetic rather than looping over floating-point reciprocals, so intermediate cancellation never loses low-order bits and the JSON result always reports a reduced fraction alongside its decimal approximation. Missing n, non-integers, fractions, scientific notation, values outside the supported range, and any n below one all fail with invalid_input and a clear message.

How inputs are read and how the closed form stays exact

Optional leading plus signs are allowed; embedded spaces, hex prefixes, and exponential notation are rejected so a bad spreadsheet cell does not become a wrong fraction. Values of n below one are rejected with an explicit message: the telescoping sum here requires n greater than or equal to one, matching the usual definition that starts at the first positive index k equals one. Pair the output with geometric-series helpers when you need other classical closed forms, or with sum-of-cubes tools when you prefer integer figurate identities instead of rational telescoping. The only required field is n, a positive integer upper bound for the partial sum, with aliases count and terms so forms and query strings can reuse one contract. Values above one million are rejected so the API stays bounded and decimal conversion remains a simple safe-integer division. Internally the engine forms the fraction n over n plus one, reduces it by the greatest common divisor of numerator and denominator (which is always one for consecutive integers, but the reduction step remains for clarity and for future extensions), and also returns the IEEE-754 double of that ratio as the sum field.

Where telescoping sums fit in study, contests, and automation

On this page the work runs entirely in your browser; through the API each successful lookup costs $0.002, failed validation is not charged, and nothing is stored after the response returns. That split — free interactive exploration and a priced, identical API — matches the rest of the KIT tier-A catalog and lets you move from a classroom demo to an automated pipeline without changing the mathematical result.

Deterministic test fixtures

Generate reproducible telescoping partial sums for unit tests, property checks, and CI assertions without embedding static tables.

What happens if n is below 1?

The request fails with invalid_input. The partial sum of 1/(k(k+1)) from k=1 to n requires n greater than or equal to one, so zero and negative indices are rejected.

Why does the series telescope?

Each term 1/(k(k+1)) equals 1/k − 1/(k+1). When you add from k=1 to n, intermediate fractions cancel and only 1 − 1/(n+1) remains, which is n/(n+1).

Read the full KIT documentation →